Here is the winning and rewarding formular:
We will reward everyone for everything, but the addition to active referrals will depend on the ratio of active over inactive:
FORMULA: If bestie A has total of 't' referrals out of which only 'y' are active, total resultant referrals T will be calculated as follows:
T = [{(t-y)/t} x y] + y
Using our table, we get the following for out top 10:
And so... T = [{(t-y)/t} x y] + y RESULTS:
1. @Makavelli25: [{(74-58)/74} x 58] + 58 = 70.54 refs
2. @Hernandez_Nicole: [{(96-54)/96} x 54] + 54 = 77.63 refs
3. @Earner30: [{(25-25)/25} x 25] + 25 = 25 refs
4. @Millyxy: [{(159-10)/159} x 10] + 10 = 19.37 refs
5. @Mrperfect : [{(13-10)/13} x 10] + 10 = 12.31 refs
6. @Nwachinemere: [{(17-5)/17} x 5] + 5 = 8.53 refs
These are the only 6 qualified since our season is in multiples of 10 refs and 5 refs.
REWARDS:
T = [{(t-y)/t} x y] + y RESULTS:
1. @Makavelli25: (70.54 refs /10)x 2,500 = 7x2,500 =
17,500
2. @Hernandez_Nicole: 77.63 refs = 7x2,500 + 1x1,500 =
18,500
3. @Earner30: 25 refs = 2x2,500 + 1x1,000 =
6,000
4. @Millyxy: 19.37 refs = 2,500 + 1,000 =
3,500
5. @Mrperfect : 12.31 refs =
2,500
6. @Nwachinemere: 8.53 refs =
1,000
TOTAL: 49000